40% off

Ends in

--d--h--mLock in £90
← All past papers

ESAT Mock Maths 2 Esat-maths2-bank-2

30 questions30 marks40Updated August 2026

The ESAT Mock Maths 2 Esat-maths2-bank-2 paper in full: all 30 questions, each with its answer. ESAT is the Engineering and Science Admissions Test. Sit it cold under exam timing, mark it, then work back through anything you missed using the solutions below.

Questions and answers are free. Full step-by-step worked solutions unlock with a free account. Start practising.

Question 1

1 mark
Which of the following functions f(x)f(x), defined for all real numbers xx, is a one-to-one mapping?
  • A.f(x)=x+2f(x) = |x + 2|
  • B.f(x)=x22xf(x) = x^2 - 2x
  • C.f(x)=x3+xf(x) = x^3 + x
  • D.f(x)=x41f(x) = x^4 - 1
  • E.f(x)=sinxf(x) = \sin x

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 2

1 mark
The sequence xkx_k is defined by x1=5x_1 = 5 and the recurrence relation xn+1=11xnx_{n+1} = 1 - \frac{1}{x_n} for n1n \ge 1. What is the value of the sum k=161xk\sum_{k=1}^{61} x_k?
  • A.111.00
  • B.112.85
  • C.116.00
  • D.116.55
  • E.338.55

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 3

1 mark
The sequence ana_n is defined by the formula an=1+1n2+2na_n = 1 + \frac{1}{n^2 + 2n} for n1n \ge 1. What is the value of the product a1×a2×imesa48a_1 \times a_2 \times \dots imes a_{48}?
  • A.0.98
  • B.1.92
  • C.1.96
  • D.1.98
  • E.2.00

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 4

1 mark
An arithmetic series has first term aa and common difference dd. Let SnS_n denote the sum of the first nn terms of the series. If S10=5S5S_{10} = 5S_5, which of the following expresses the relationship between aa and dd?
  • A.d=3ad = -3a
  • B.d=3ad = 3a
  • C.a=3da = -3d
  • D.d=ad = -a
  • E.a=3da = 3d

Answer: A

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 5

1 mark
The line L1L_1 passes through the points A(2,5)A(-2, 5) and B(4,2)B(4, 2). A second line L2L_2 is perpendicular to L1L_1 and passes through the midpoint of the line segment ABAB. Which of the following is the equation of L2L_2?
  • A.4x - 2y + 3 = 0
  • B.4x - 2y - 1 = 0
  • C.x + 2y - 8 = 0
  • D.4x + 2y - 11 = 0
  • E.2x - 4y + 13 = 0

Answer: A

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 6

1 mark
The lines with equations 3xy+4=03x - y + 4 = 0 and x+2y1=0x + 2y - 1 = 0 intersect at the point PP. A third line LL passes through PP and is parallel to the line y=5x7y = 5x - 7. What is the equation of the line LL?
  • A.5x - y + 6 = 0
  • B.5x - y - 4 = 0
  • C.x + 5y - 4 = 0
  • D.5x + y + 4 = 0
  • E.3x - y + 4 = 0

Answer: A

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 7

1 mark
A triangle ABCABC has side lengths AB=12AB = 12 and BC=8BC = 8. The angle BAC=θ\angle BAC = \theta is such that two non-congruent triangles are possible for this specific value of θ\theta. If the difference between the areas of these two possible triangles is 16316\sqrt{3}, what is the value of sinθ\sin \theta?
  • A.16\frac{1}{6}
  • B.13\frac{1}{3}
  • C.12\frac{1}{2}
  • D.23\frac{2}{3}
  • E.34\frac{3}{4}

Answer: B

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 8

1 mark
A chord of length LL in a circle of radius rr divides the circle into two segments. The area of the minor segment is AsegA_{\text{seg}} and the area of the triangle formed by the chord and the centre of the circle is AtriA_{\text{tri}}. Given that 33(Aseg+Atri)=4πAtri3\sqrt{3}(A_{\text{seg}} + A_{\text{tri}}) = 4\pi A_{\text{tri}}, which one of the following is the value of LL?
  • A.rr
  • B.32r\frac{\sqrt{3}}{2}r
  • C.2r\sqrt{2}r
  • D.3r\sqrt{3}r
  • E.2r2r

Answer: D

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 9

1 mark
A sequence of right-angled triangles T1,T2,T3,T_1, T_2, T_3, \dots is constructed such that for each n1n \geq 1:
- The hypotenuse of
T1T_1 has length 11.
- Each triangle
TnT_n contains an angle of 3030^\circ.
- The hypotenuse of
Tn+1T_{n+1} is the side of TnT_n adjacent to the 3030^\circ angle.
Find the sum of the areas of all triangles in the infinite sequence.
  • A.34\frac{\sqrt{3}}{4}
  • B.3\sqrt{3}
  • C.32\frac{\sqrt{3}}{2}
  • D.36\frac{\sqrt{3}}{6}
  • E.12\frac{1}{2}

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 10

1 mark
Find the complete set of values of xx in the interval 0xπ0 \le x \le \pi for which the inequality cos(2x)<cos(x)\cos(2x) < \cos(x) is satisfied.
  • A.0<x<π30 < x < \frac{\pi}{3}
  • B.0<x<2π30 < x < \frac{2\pi}{3}
  • C.π3<x<2π3\frac{\pi}{3} < x < \frac{2\pi}{3}
  • D.2π3<x<π\frac{2\pi}{3} < x < \pi
  • E.π3<x<π\frac{\pi}{3} < x < \pi

Answer: B

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 11

1 mark
How many solutions does the equation sin(2x)=sin(x2)\sin(2x) = \sin\left(\frac{x}{2}\right) have in the interval 0x2π0 \le x \le 2\pi?
  • A.2
  • B.3
  • C.4
  • D.5
  • E.6

Answer: D

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 12

1 mark
An angle θ\theta satisfies the conditions tanθ=34\tan \theta = \frac{3}{4} and cosθ<0\cos \theta < 0. What is the value of sinθ\sin \theta?
  • A.0.8-0.8
  • B.0.6-0.6
  • C.0.60.6
  • D.0.80.8
  • E.0.750.75

Answer: B

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 13

1 mark
Find the sum of all possible values of xx in the range 0x2π0 \le x \le 2\pi which satisfy the equation

4sin4x+cos2x=14 \sin^4 x + \cos^2 x = 1


Give your answer in radians.
  • A.2π2\pi
  • B.3π3\pi
  • C.4π4\pi
  • D.5π5\pi
  • E.7π7\pi

Answer: E

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 14

1 mark
Find the number of real solutions of the equation

tanx+cosx=secx\tan x + \cos x = \sec x


in the range
0x2π0 \le x \le 2\pi.
  • A.1
  • B.2
  • C.3
  • D.4
  • E.5

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 15

1 mark
The graph of y=2xy = 2^x is reflected in the yy-axis and then translated by cc units in the positive yy-direction to produce the graph of y=g(x)y = g(x). The point (2,13)(-2, 13) lies on the graph of gg. What is the yy-intercept of the graph of gg?
  • A.8
  • B.9
  • C.10
  • D.11
  • E.13

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 16

1 mark
The curves C1C_1 and C2C_2 have equations y=2x+13y = 2^x + 13 and y=2x+2+1y = 2^{x+2} + 1 respectively. What is the xx-coordinate of the point of intersection of C1C_1 and C2C_2?
  • A.1
  • B.2
  • C.3
  • D.4
  • E.6

Answer: B

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 17

1 mark
Given that b>1b > 1 and xx and yy are positive real numbers such that:
logb(x2y)=8\log_b(x^2 y) = 8

logb(xy2)=1\log_b\left(\frac{x}{y^2}\right) = -1

what is the value of
logb(xy2)\log_b(xy^2)?
  • A.2
  • B.3
  • C.5
  • D.7
  • E.8

Answer: D

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 18

1 mark
The function ff is defined for x>0x > 0 by f(x)=ax+bx2f(x) = \frac{a}{x} + bx^2, where aa and bb are non-zero constants. The tangent to the graph y=f(x)y = f(x) at x=2x = 2 has the equation y=2x4y = 2x - 4. What is the value of f(1)f''(1)?
  • A.143-\frac{14}{3}
  • B.73-\frac{7}{3}
  • C.00
  • D.103\frac{10}{3}
  • E.143\frac{14}{3}

Answer: A

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 19

1 mark
A curve has the equation y=x3+ax2+bx+5y = x^3 + ax^2 + bx + 5, where aa and bb are constants. The gradient of the curve at x=1x = 1 is 11. The rate of change of this gradient with respect to xx is zero at x=2x = 2. What is the minimum possible value of the gradient of this curve?
  • A.12-12
  • B.6-6
  • C.2-2
  • D.11
  • E.1010

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 20

1 mark
The curve CC has equation y=x2163xx+10xy = x^2 - \frac{16}{3}x\sqrt{x} + 10x for x>0x > 0.

What is the minimum possible value of the gradient of
CC?
  • A.2
  • B.4
  • C.0
  • D.10
  • E.-8

Answer: A

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 21

1 mark
The curve CC has the equation y=3x212x+7y = 3x^2 - 12x + 7. The line LL is normal to the curve CC at the point where x=1x = 1.

The
xx-coordinate of the point where the line LL cuts the x-axis is
  • A.11-11
  • B.11
  • C.1111
  • D.1313
  • E.1515

Answer: D

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 22

1 mark
The function f(x)=x3+bx2+12x+5f(x) = x^3 + bx^2 + 12x + 5, where bb is a real constant, is defined for all real xx.

The complete set of values of
bb for which f(x)>0f'(x) > 0 for all real xx is
  • A.b<6b < -6 or b>6b > 6
  • B.b>6b > -6
  • C.6<b<6-6 < b < 6
  • D.6b6-6 \leq b \leq 6
  • E.12<b<12-12 < b < 12

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 23

1 mark
What is the area of the finite region bounded by the curve y=(x1)2xy = \frac{(x-1)^2}{\sqrt{x}}, the xx-axis, and the lines x=1x = 1 and x=4x = 4?
  • A.7615\frac{76}{15}
  • B.1615\frac{16}{15}
  • C.9215\frac{92}{15}
  • D.4615\frac{46}{15}
  • E.10615\frac{106}{15}

Answer: A

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 24

1 mark
The gradient of a curve is given by dydx=x(x+1x2)\frac{dy}{dx} = \sqrt{x} \left( x + \frac{1}{x^2} \right) for x>0x > 0. Given that the curve passes through the point (4,10)(4, 10), find the yy-coordinate of the point on the curve where x=1x = 1.
  • A.175-\frac{17}{5}
  • B.75-\frac{7}{5}
  • C.15\frac{1}{5}
  • D.95-\frac{9}{5}
  • E.35\frac{3}{5}

Answer: A

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 25

1 mark
A continuous function ff is defined for all t>0t > 0 and satisfies the equation:
4x2f(t)dt=x38\int_4^{x^2} f(t) \, dt = x^3 - 8

for all
x>0x > 0. What is the value of f(9)f(9)?
  • A.1.5
  • B.3.0
  • C.4.5
  • D.13.5
  • E.27.0

Answer: C

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 26

1 mark
A continuous function f(x)f(x) satisfies the following conditions:
04f(x)dx=10\int_0^4 f(x) \, dx = 10

24f(x)dx=6\int_2^4 f(x) \, dx = 6

What is the value of
01[f(2x)+3]dx\int_0^1 [f(2x) + 3] \, dx?
  • A.2
  • B.5
  • C.6
  • D.7
  • E.8

Answer: B

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 27

1 mark
A student uses the trapezium rule with nn equal strips (n>1n > 1) to estimate the area under each of the following three curves between x=0x = 0 and x=1x = 1:

(1)
y=ln(x+1)y = \ln(x + 1)
(2)
y=ln(2x+1)y = \ln\left(\frac{2}{x + 1}\right)
(3)
y=ln(2x)y = \ln(2 - x)

For which of these curves does the rule produce an underestimate?
  • A.(1) only
  • B.(3) only
  • C.(1) and (2) only
  • D.(1) and (3) only
  • E.(1), (2) and (3)

Answer: D

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 28

1 mark
The trapezium rule with nn equal strips is used to estimate the integral:

02(2xx2)dx\int_{0}^{2} (2x - x^2) \, dx


Which of the following is the correct expression for the estimate produced?
  • A.4n233n2\frac{4n^2 - 3}{3n^2}
  • B.4(n21)3n2\frac{4(n^2 - 1)}{3n^2}
  • C.4(n2+1)3n2\frac{4(n^2 + 1)}{3n^2}
  • D.4n223n2\frac{4n^2 - 2}{3n^2}
  • E.4(n1)3n\frac{4(n - 1)}{3n}

Answer: B

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 29

1 mark
The function f(x)=ln(x+a)+bf(x) = \ln(x + a) + b, where aa and bb are real constants, passes through the origin (0,0)(0, 0) and the point (e21,2)(e^2 - 1, 2). What is the value of f(e1)f(e - 1)?
  • A.00
  • B.11
  • C.22
  • D.ee
  • E.e1e - 1

Answer: B

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →

Question 30

1 mark
How many distinct real solutions are there to the equation (x1)2(x4)=2|(x - 1)^2 (x - 4)| = 2?
  • A.11
  • B.22
  • C.33
  • D.44
  • E.55

Answer: D

Full step-by-step worked solution

Locked. Available with a free account.

Unlock worked solutions →
ESAT Mock Maths 2 Esat-maths2-bank-2: Questions & Worked Solutions | esat.fyi