Changing the Subject of a Formula for ESAT

Updated July 2026

Rearranging formulae is a critical algebraic skill for the ESAT Mathematics 1 section. It involves manipulating an equation to express a specific variable in terms of others. This process is essential for solving complex engineering and science problems where a particular unknown must be isolated and calculated from known quantities.

Core concept

Changing the subject of a formula means rearranging an equation so that one chosen variable, the subject, is isolated on one side of the equals sign, while all other variables and constants are on the opposite side: x=f(y,z,...)x = f(y, z, ...).

The Fundamental Rules of Rearranging

Changing the subject of a formula requires expressing one variable in terms of the other variables. To achieve this, the formula must be rearranged according to the standard rules of arithmetic and algebra. The goal is to perform operations that isolate the new subject. The following operations can be applied to both sides of a formula to maintain equality:

  1. You can add or subtract the same quantity or term from each side.
  2. You can multiply or divide both sides by the same non-zero quantity.
  3. You can invert both sides of a formula if both sides consist of a single fraction with non-zero denominators.
  4. You can square both sides or raise both sides to the same non-zero power.
  5. You can take the square root of both sides.

Changing the Subject Using Subtraction

When the variable you wish to isolate appears in multiple terms or alongside other variables, you must first group the terms containing that variable. Consider the following example where we make pp the subject of the formula:

q+2p=p+4q6rq + 2p = p + 4q - 6r

First, subtract pp from both sides to ensure all terms containing pp are on the same side: q+2pp=4q6rq + 2p - p = 4q - 6r

Collect the like terms on the left side: q+p=4q6rq + p = 4q - 6r

Next, subtract qq from both sides to isolate the pp term: p=4q6rqp = 4q - 6r - q

Collect the like terms on the right side: p=3q6rp = 3q - 6r

Finally, factorise the expression by taking out the common factor of 3 to simplify the result: p=3(q2r)p = 3(q - 2r)

Changing the Subject Using the Four Functions

In more complex formulae involving brackets and fractions, it is often necessary to expand and multiply out denominators before isolating the subject. Consider making xx the subject of the following formula:

y=3(x2)+x2y = 3(x - 2) + \frac{x}{2}

First, multiply out the bracket on the right hand side: y=3x6+x2y = 3x - 6 + \frac{x}{2}

To eliminate the fraction, multiply both sides of the formula by 2: 2y=6x12+x2y = 6x - 12 + x

Collect the like terms involving xx: 2y=7x122y = 7x - 12

Add 12 to both sides to further isolate the xx term: 2y+12=7x2y + 12 = 7x

Finally, divide by 7 to make xx the subject: x=2y+127x = \frac{2y + 12}{7}

Variables in the Denominator of a Fraction

If the variable you wish to isolate is located in the denominator, you must move it to the numerator. This often involves finding a common denominator or inverting the fractions. For example, make uu the subject of this formula:

1v1u=1p\frac{1}{v} - \frac{1}{u} = \frac{1}{p}

First, rearrange the formula to isolate the term containing uu on one side: 1v1p=1u\frac{1}{v} - \frac{1}{p} = \frac{1}{u}

Now, combine the terms on the left hand side by placing them over a common denominator, which is vpvp: pvvp=1u\frac{p - v}{vp} = \frac{1}{u}

Since both sides are now single fractions, you can invert both fractions, essentially turning them both upside down: vppv=u1\frac{vp}{p - v} = \frac{u}{1}

This gives the final result: u=vppvu = \frac{vp}{p - v}

Formulae Involving Square Roots

When a variable is trapped inside a square root, you must apply the inverse operation, which is squaring, to free it. Consider making xx the subject of the formula below:

y=3x+54y = \sqrt{\frac{3x + 5}{4}}

First, square both sides of the formula: y2=3x+54y^2 = \frac{3x + 5}{4}

Now, rearrange the formula to isolate xx. Multiply both sides by 4: 4y2=3x+54y^2 = 3x + 5

Subtract 5 from both sides: 4y25=3x4y^2 - 5 = 3x

Finally, divide by 3 to isolate xx completely: x=4y253x = \frac{4y^2 - 5}{3}

Key takeaways

  • Always apply identical operations to both sides of the equation to maintain balance.
  • If the subject appears in more than one term, collect those terms on one side and factorise.
  • Eliminate fractions by multiplying by the denominator or by using common denominators followed by inversion.
  • Use inverse operations systematically: addition is reversed by subtraction, and square roots are reversed by squaring.
Tips

Always check your work by substituting small numerical values into both the original and the rearranged formula. If the results are consistent, your rearrangement is likely correct. In the ESAT, speed is key, so look for the most direct path to isolate the variable, such as clearing denominators early.

Cautions

A frequent error is only multiplying one term by a quantity instead of the entire side. For instance, in y=3x+2y = 3x + 2, multiplying by 2 results in 2y=6x+42y = 6x + 4, not 2y=6x+22y = 6x + 2. Every term on both sides must be multiplied or divided equally.

Insight

Rearranging formulae is the logical foundation for functions and their inverses. By changing the subject, you are essentially finding the inverse mapping of the original relationship, which is a core concept across calculus and higher-level mathematics in the ESAT.

Frequently asked questions

Can I invert both sides of an equation if one side has two separate terms?

No, you can only invert both sides if each side is a single fraction. If one side has multiple terms, you must first combine them into a single fraction using a common denominator before inverting.

What should I do if the subject I want is part of a term with a negative sign?

It is often easiest to add that term to both sides so that the subject becomes positive. For example, if you have y=axy = a - x, adding xx to both sides gives y+x=ay + x = a, which makes further isolation simpler.

Is it necessary to factorise the final answer?

While not always strictly required unless specified, factorising often provides a cleaner and more professional form of the result, such as p=3(q2r)p = 3(q - 2r) instead of p=3q6rp = 3q - 6r.

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