Ratio and Proportion for ESAT Mathematics

Updated July 2026

Master the principles of ratio and proportion required for the ESAT. This page explains how to solve proportional problems using unitary and HCF methods, combine multiple ratios into single fractions, and convert ratios into linear functions. Understanding these relationships is vital for managing complex variables in both pure mathematics and applied science sections.

Core concept

Proportion defines a constant ratio between quantities. If x:y=a:bx:y = a:b, then the fraction of xx in the total is aa+b\frac{a}{a+b}, and the relationship can be expressed as a linear function y=baxy = \frac{b}{a}x.

Simple Proportion

Simple proportion problems involve finding a new quantity based on a known relationship between two values. If it is known that xx items cost Ey\mathcal{E}y, we can determine the cost of any other number of items, aa, using two primary techniques.

Method 1: The Unitary Method

In the unitary method, you first find the value of a single unit. Consider the following example: If 12 boxes of biscuits cost 42, how much do 20 boxes cost?

  1. Find the cost of one box: 1 box costs 42÷1242 \div 12. It is best not to divide this out at this stage unless it results in an integer, to avoid rounding errors.

  2. Multiply by the required number: 20 boxes cost 42÷12×2042 \div 12 \times 20.

  3. Simplify the calculation: 42÷12×20=42×201242 \div 12 \times 20 = \frac{42 \times 20}{12}. Dividing the numerator and denominator by 6 gives 7×202\frac{7 \times 20}{2}. Further dividing by 2 gives 7×101=70\frac{7 \times 10}{1} = 70. Thus, 20 boxes cost 70.

Method 2: Using the Highest Common Factor (HCF)

Alternatively, you can use the Highest Common Factor of the given and required quantities to simplify the arithmetic. Using the same example of 12 and 20 boxes:

  1. The HCF of 12 and 20 is 4. Therefore, calculate the cost of 4 boxes.

  2. Since 12 boxes cost 42, 4 boxes cost one third of that: 42÷3=1442 \div 3 = 14.

  3. Since 20 boxes is five times 4 boxes, multiply the cost by 5: 14×5=7014 \times 5 = 70. This confirms the cost of 20 boxes is 70.

Relating Ratios to Fractions

If a mixture consists only of two components xx and yy in the ratio a:ba:b, the fraction of the total mixture made up by xx is aa+b\frac{a}{a+b}. When dealing with multiple ratios, you must find a common link to combine them into a single ratio string.

Example: A packet of sweets contains yellow, green, and red sweets. The ratio of yellow to green is 3:43:4 and the ratio of green to red is 6:96:9. To find what fraction of the pack is yellow, we must find the combined ratio yellow:green:redyellow:green:red.

  1. Identify the common component, which is green sweets. In the first ratio, green is 4, and in the second, it is 6.

  2. Express 3:43:4 in terms of 6 by multiplying by 32\frac{3}{2} or 1.5. This gives 3×1.5:4×1.53 \times 1.5 : 4 \times 1.5, which is 4.5:64.5:6.

  3. The combined ratio is 4.5:6:94.5:6:9. To work with integers, multiply through by 2 to get 9:12:189:12:18.

  4. Calculate the fraction of yellow sweets: 99+12+18=939\frac{9}{9+12+18} = \frac{9}{39}. Simplified, this is 313\frac{3}{13}.

Relating Ratios to Linear Functions

Ratios can also be expressed as algebraic relationships between two variables. If the ratio x:yx:y is a:ba:b, then the relationship is bx=aybx = ay or y=baxy = \frac{b}{a}x.

Consider the ratio x:y=2:3x:y = 2:3. To write yy as a linear function of xx:

  1. Convert the ratio into a fractional equation: xy=23\frac{x}{y} = \frac{2}{3}.

  2. Multiply both sides by yy: x=23yx = \frac{2}{3}y.

  3. Multiply both sides by 3 to remove the denominator: 3x=2y3x = 2y.

  4. Divide both sides by 2 to isolate yy: y=3x2y = \frac{3x}{2}, or y=1.5xy = 1.5x. This shows that yy is a linear function of xx passing through the origin.

Key takeaways

  • The unitary method calculates the value of one unit before scaling, while the HCF method uses the largest common factor between quantities to simplify steps.
  • To combine two ratios like a:ba:b and b:cb:c, the shared variable bb must be adjusted to the same value in both ratios.
  • The fraction of a part in a ratio is calculated by dividing its value by the sum of all parts in the ratio.
  • A ratio x:y=a:bx:y = a:b always defines a linear relationship y=baxy = \frac{b}{a}x, which is a straight line through the origin.
Tips

When combining ratios, look for the lowest common multiple of the shared component to keep your final integers as small as possible.

Cautions

Never add components from different ratios directly without first ensuring they have been scaled to a common reference value.

Insight

The relationship y=baxy = \frac{b}{a}x derived from a ratio x:y=a:bx:y = a:b is an example of direct proportionality. In such functions, the constant of proportionality kk is equal to ba\frac{b}{a}.

Frequently asked questions

What should I do if the unitary method results in a recurring decimal?

In the ESAT, you should leave the value as a fraction (e.g., 42/1242/12) and perform your multiplications and divisions as a single operation to allow for simplification and maintain exactness.

Can I combine ratios with three or more parts using the same method?

Yes, as long as there is a shared component between the ratios. You scale the ratios until the common parts have identical numerical values across all individual ratios.

Does a ratio of x:y=2:3x:y = 2:3 mean yy is twice as large as xx?

No, it means xx is two parts and yy is three parts. Algebraically, this means y=1.5xy = 1.5x, so yy is actually 50 percent larger than xx.

Why is the HCF method taught alongside the unitary method?

The HCF method is often more efficient for mental arithmetic in exam conditions, especially when the numbers involved share obvious factors like 4, 5, or 10.

Ready to test your knowledge?

You've reached the end of this section. Start a practice session to solidify your understanding and master this topic.